|
|
|
|
LEADER |
01436nam a2200289 u 4500 |
001 |
10094441 |
003 |
GR-PaULI |
005 |
20210117203036.0 |
008 |
110831r19731957uk eng |
020 |
|
|
|a 0691023565
|q (χαρτόδετο)
|
020 |
|
|
|a 0691080976
|q (σκληρό εξώφυλλο)
|
040 |
|
|
|a GR-PaULI
|c GR-PaULI
|b gre
|e AACR2
|
082 |
0 |
4 |
|a 510.7
|2 23
|
100 |
1 |
|
|a Polya, George
|d 1887-1985
|9 4388
|e συγγραφέας.
|
245 |
1 |
0 |
|a How to solve it :
|b a new aspect of mathematical method /
|c G. Polya.
|
250 |
|
|
|a 2nd ed.
|
260 |
|
|
|a Princeton :
|b Princeton University Press,
|c 1973.
|
300 |
|
|
|a xxi, 253 σ. ;
|c 20 εκ.
|
500 |
|
|
|a
|
650 |
|
4 |
|a Μαθηματικές μέθοδοι
|9 2225
|
650 |
|
4 |
|9 27841
|a Μαθηματικά
|x Προβλήματα, ασκήσεις κλπ.
|
942 |
|
|
|2 ddc
|c BK15
|
952 |
|
|
|0 0
|1 0
|4 0
|6 510_700000000000000_POL
|7 0
|9 102533
|a LISP
|b LISP
|c BSC
|d 2016-04-24
|i 092338
|l 1
|m 1
|o 510.7 POL
|p 025000038223
|r 2023-12-20 00:00:00
|s 2023-11-10
|t 1
|v 2016.00
|w 2016-04-24
|y BK15
|
952 |
|
|
|0 0
|1 0
|4 0
|6 510_700000000000000_POL
|7 0
|9 102534
|a LISP
|b LISP
|c BSC
|d 2016-04-24
|i 106593
|l 0
|o 510.7 POL
|p 025000038224
|r 2016-04-24 00:00:00
|t 2
|v 2016.00
|w 2016-04-24
|y BK15
|
952 |
|
|
|0 0
|1 0
|2 ddc
|4 0
|6 510_700000000000000_POL
|7 0
|9 224927
|a LISP
|b LISP
|c DON
|d 2018-07-27
|e ΚΝΖ
|i 092375
|l 0
|o 510.7 POL
|p 025000159373
|r 2018-07-27 00:00:00
|t 3
|v 2018.00
|w 2018-07-27
|y BK15
|
998 |
|
|
|c ΜΠΟΥΡΑΣ
|d 2011-08
|
999 |
|
|
|c 70140
|d 70140
|